Derf
Pinnacle OPE Member
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By my math, you get 11 different 3-saw plans....
Actually, there are many more permutations than 11 different 3-saw plans if you have 33 saws to choose from.
1, 2, 3.
2, 3, 4.
3, 4, 5.... etc. That would get you at least 31 3-saw plans...
Then you have
1, 2, 4.
1, 2, 5.
1, 2, 6.... etc.
Then you have
1, 3, 4.
1, 3, 5....
One could say that a permutation is an ordered combination. The number of permutations of n objects taken r at a time is determined by the formula: P ( n , r ) = n ! ( n − r ) ! but if order isn't important and repetition isn't allowed, the formulas would be (n !) / r! (n-r)!
The math works out to 5456 possible 3-saw plans if you have 33 saws. (I was a math minor in a previous life).